NEET-XII-Physics
13: Nuclei
- #18A 1000 MW fission reactor consumes half of its fuel in 5.00 y. How much
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did it contain initially? Assume that the reactor operates 80% of the time, that all the energy generated arises from the fission of and that this nuclide is consumed only by the fission process.
Ans : Half life of the fuel of the fission reactor,
years
= 5 × 365 × 24 × 60 × 60 s
We know that in the fission of 1 g ofnucleus, the energy released is equal to 200 MeV.
1 mole, i.e., 235 g ofcontains 6.023 × 1023 atoms.
∴1 g contains
The total energy generated per gram ofis calculated as:
The reactor operates only 80% of the time.
Hence, the amount ofconsumed in 5 years by the 1000 MW fission reactor is calculated as:
∴Initial amount of= 2 × 1538 = 3076 kg