Qstnid -7- The Amplitude Of The Magnetic Field Part Of A Harmonic Electromagnetic Wave In Vacuum Is <I>b</i><sub>0</sub> = 510 Nt. What Is The Amplitude Of The Electric Field Part Of The Wave? - 08: Electromagnetic Waves - Neet-xii-physics

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NEET-XII-Physics

08: Electromagnetic Waves

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#7
The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B₀ = 510 nT. What is the amplitude of the electric field part of the wave?

Ans : Amplitude of magnetic field of an electromagnetic wave in a vacuum,

B₀ = 510 nT = 510 × 10^-9 T

Speed of light in a vacuum, c = 3 × 10⁸ m/s

Amplitude of electric field of the electromagnetic wave is given by the relation,

E = cB₀

= 3 × 10⁸× 510 × 10^-9= 153 N/C

Therefore, the electric field part of the wave is 153 N/C.