NEET-XII-Physics
07: Alternating Current
- #8Suppose the initial charge on the capacitor in Exercise 7.7 is 6 mC. What is the total energy stored in the circuit initially? What is the total energy at later time?
Ans : Capacitance of the capacitor, C = 30 μF = 30×10-6 F
Inductance of the inductor, L = 27 mH = 27 × 10-3 H
Charge on the capacitor, Q = 6 mC = 6 × 10-3 C
Total energy stored in the capacitor can be calculated by the relation,
Total energy at a later time will remain the same because energy is shared between the capacitor and the inductor.