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NEET-XII-Physics

06: Electromagnetic Induction

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  • #8
    Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, give an estimate of the self-inductance of the circuit.
    Ans : Initial current, I1 = 5.0 A

    Final current, I2 = 0.0 A

    Change in current,

    Time taken for the change, t = 0.1 s

    Average emf, e = 200 V

    For self-inductance (L) of the coil, we have the relation for average emf as:

    e = L



    Hence, the self induction of the coil is 4 H.