NEET-XII-Physics
06: Electromagnetic Induction
- #3A long solenoid with 15 turns per cm has a small loop of area 2.0 cm2 placed inside the solenoid normal to its axis. If the current carried by the solenoid changes steadily from 2.0 A to 4.0 A in 0.1 s, what is the induced emf in the loop while the current is changing?
Ans : Number of turns on the solenoid = 15 turns/cm = 1500 turns/m
Number of turns per unit length, n = 1500 turns
The solenoid has a small loop of area, A = 2.0 cm2 = 2 × 10-4 m2
Current carried by the solenoid changes from 2 A to 4 A.
Change in current in the solenoid, di = 4 - 2 = 2 A
Change in time, dt = 0.1 s
Induced emf in the solenoid is given by Faraday’s law as:
Where,
= Induced flux through the small loop
= BA ... (ii)
B = Magnetic field
=
μ0 = Permeability of free space
= 4``\pi``×10-7 H/m
Hence, equation (i) reduces to:
Hence, the induced voltage in the loop is