NEET-XII-Physics

04: Moving Charges And Magnetism

  • #7
    Two long and parallel straight wires A and B carrying currents of 8.0 A and 5.0 A in the same direction are separated by a distance of 4.0 cm. Estimate the force on a 10 cm section of wire A.
    Ans : Current flowing in wire A, IA = 8.0 A

    Current flowing in wire B, IB = 5.0 A

    Distance between the two wires, r = 4.0 cm = 0.04 m

    Length of a section of wire A, l = 10 cm = 0.1 m

    Force exerted on length l due to the magnetic field is given as:



    Where,

    = Permeability of free space = 4``\pi`` × 10-7 T m A-1



    The magnitude of force is 2 × 10-5 N. This is an attractive force normal to A towards B because the direction of the currents in the wires is the same.