NEET-XII-Physics
02: Electrostatic Potential And Capacitance
- #9Explain what would happen if in the capacitor given in Exercise 2.8, a 3 mm thick mica sheet (of dielectric constant = 6) were inserted between the plates,
(a) While the voltage supply remained connected.
(b) After the supply was disconnected.
(a) While the voltage supply remained connected.
(b) After the supply was disconnected.Ans : null (a) Dielectric constant of the mica sheet, k = 6
Initial capacitance, C = 1.771 × 10-11 F
Supply voltage, V = 100 V
Potential across the plates remains 100 V.
(b) Dielectric constant, k = 6
Initial capacitance, C = 1.771 × 10-11 F
If supply voltage is removed, then there will be no effect on the amount of charge in the plates.
Charge = 1.771 × 10-9 C
Potential across the plates is given by,
(a) Dielectric constant of the mica sheet, k = 6
Initial capacitance, C = 1.771 × 10-11 F
Supply voltage, V = 100 V
Potential across the plates remains 100 V.
(b) Dielectric constant, k = 6
Initial capacitance, C = 1.771 × 10-11 F
If supply voltage is removed, then there will be no effect on the amount of charge in the plates.
Charge = 1.771 × 10-9 C
Potential across the plates is given by,
- #9-aWhile the voltage supply remained connected.Ans : Dielectric constant of the mica sheet, k = 6
Initial capacitance, C = 1.771 × 10-11 F
Supply voltage, V = 100 V
Potential across the plates remains 100 V.
- #9-bAfter the supply was disconnected.Ans : Dielectric constant, k = 6
Initial capacitance, C = 1.771 × 10-11 F
If supply voltage is removed, then there will be no effect on the amount of charge in the plates.
Charge = 1.771 × 10-9 C
Potential across the plates is given by,