Qstnid -34- Suppose That The Particle In Exercise In 1.33 Is An Electron Projected With Velocity <I>v</i><sub><i>x</i></sub>= 2.0 &Times; 10<sup>6</sup> M S<sup>-1</sup>. If <I>e </I>between The Plates Separated By 0.5 Cm Is 9.1 &Times; 10<sup>2</sup> N/c, Where Will The Electron Strike The Upper Plate? (| <I>e </I>| =1.6 &Times; 10<sup>-19</sup> C, <I>m</i><sub><i>e </I></sub>= 9.1 &Times; 10<sup>-31</sup> Kg.) - 01: Electric Charges And Fields - Neet-xii-physics

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NEET-XII-Physics

01: Electric Charges And Fields

I - page 6

Qstn# 34 Prvs-Qstn

#34
Suppose that the particle in Exercise in 1.33 is an electron projected with velocity v_x= 2.0 × 10⁶ m s^-1. If E between the plates separated by 0.5 cm is 9.1 × 10² N/C, where will the electron strike the upper plate? (| e | =1.6 × 10^-19 C, m_e= 9.1 × 10^-31 kg.)

Ans : Velocity of the particle, v_x = 2.0 × 10⁶ m/s

Separation of the two plates, d = 0.5 cm = 0.005 m

Electric field between the two plates, E = 9.1 × 10² N/C

Charge on an electron, q = 1.6 × 10^-19 C

Mass of an electron, m_e= 9.1 × 10^-31 kg

Let the electron strike the upper plate at the end of plate L, when deflection is s.

Therefore,

Therefore, the electron will strike the upper plate after travelling 1.6 cm.