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NEET-XII-Chemistry

01: Haloalkanes and Haloarenes

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    1 - Haloalkanes and Haloarenes
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    Section : I
    SECTION I Page No 285:
  • Qstn #1
    Write structures of the following compounds:
  • Qstn #1-i
    2-Chloro-3-methylpentane
    Ans :

    2-Chloro-3-methyl pentane
  • Qstn #1-ii
    1-Chloro-4-ethylcyclohexane
    Ans :

    1-Chloro-4-ethylcyclohexane
  • Qstn #1-iii
    4-tert. Butyl-3-iodoheptane
    Ans :

    4- tert-Butyl-3-iodoheptane
  • Qstn #1-iv
    1,4-Dibromobut-2-ene
    Ans :

    1, 4-Dibromobut-2-ene
  • Qstn #1-v
    1-Bromo-4-sec. butyl-2-methylbenzene
    Ans :

    1-Bromo-4-sec-butyl-2-methylbenzene
  • Qstn #2
    Why is sulphuric acid not used during the reaction of alcohols with KI?
    Ans : In the presence of sulphuric acid (H2SO4), KI produces HI



    Since

    is an oxidizing agent, it oxidizes HI (produced in the reaction to I2).



    As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4 is used.
  • Qstn #3
    Write structures of different dihalogen derivatives of propane.
    Ans : There are four different dihalogen derivatives of propane. The structures of these derivatives are shown below.

    (i)



    1, 1-Dibromopropane

    (ii)



    2, 2-Dibromopropane

    (iii)



    1, 2-Dibromopropane

    (iv)



    1, 3-Dibromopropane
  • Qstn #4
    Among the isomeric alkanes of molecular formula C5H12, identify the one that on photochemical chlorination yields
  • Qstn #4-i
    A single monochloride.
    Ans : To have a single monochloride, there should be only one type of H-atom in the isomer of the alkane of the molecular formula C5H12. This is because, replacement of any H-atom leads to the formation of the same product. The isomer is neopentane.



    Neopentane
  • Qstn #4-ii
    Three isomeric monochlorides.
    Ans : To have three isomeric monochlorides, the isomer of the alkane of the molecular formula C5H12 should contain three different types of H-atoms.

    Therefore, the isomer is n-pentane. It can be observed that there are three types of H atoms labelled as a, b and c in n-pentane.


  • Qstn #4-iii
    Four isomeric monochlorides.
    Ans : To have four isomeric monochlorides, the isomer of the alkane of the molecular formula C5H12 should contain four different types of H-atoms. Therefore, the isomer is 2-methylbutane. It can be observed that there are four types of H-atoms labelled as a, b, c, and d in 2-methylbutane.


  • Qstn #5
    Draw the structures of major monohalo products in each of the following reactions:
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