Qstnid -9- A Car Weighs 1800 Kg. The Distance Between Its Front And Back Axles Is 1.8 M. Its Centre Of Gravity Is 1.05 M Behind The Front Axle. Determine The Force Exerted By The Level Ground On Each Front Wheel And Each Back Wheel. - 07: System Of Particles And Rotational Motion - Neet-xi-physics

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NEET-XI-Physics

07: System of particles and Rotational Motion

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#9
A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front wheel and each back wheel.
Ans : Let F₁ and F₂ be the forces exerted by the level groundon front wheels and back wheels respectively.Considering rotational equilibrium about the front wheels,F₂ x 1.8 = mg x 1.05or F₂ = 1.05/1.8 x 1800 x 9.8 N =10290 NForce on each back wheel is =10290/2 N or 5145 N.

Considering rotational equilibrium about the back wheels.

F₁ x 1.8 = mg (1.8 - 1.05) = 0.75 x 1800 x 9.8

or F₁=0.75 x 1800 x 9.8/1.8 = 7350 N

Force on each front wheel is 7350/2 N or 3675 N.