NEET-XI-Chemistry
06: Hydrocarbons
- #12Explain why the following systems are not aromatic?
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Ans : null ()
For the given compound, the number of ``\pi``-electrons is six. But only four ``\pi``-electrons are present within the ring. Also there is no conjugation of``\pi``-electrons within the ring and the compound is not planar in shape. Hence, the given compound is not aromatic in nature.
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For the given compound, the number of ``\pi``-electrons is four.
By Huckel’s rule,
4n + 2 = 4
4n = 2
For a compound to be aromatic, the value of n must be an integer (n = 0, 1, 2...), which is not true for the given compound. Hence, it is not aromatic in nature.
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For the given compound, the number of ``\pi``-electrons is eight.
By Huckel’s rule,
4n + 2 = 8
4n = 6
For a compound to be aromatic, the value of n must be an integer (n = 0, 1, 2...). Since the value of n is not an integer, the given compound is not aromatic in nature.
()
For the given compound, the number of ``\pi``-electrons is four.
By Huckel’s rule,
4n + 2 = 4
4n = 2
For a compound to be aromatic, the value of n must be an integer (n = 0, 1, 2...), which is not true for the given compound. Hence, it is not aromatic in nature.
()
For the given compound, the number of ``\pi``-electrons is eight.
By Huckel’s rule,
4n + 2 = 8
4n = 6
For a compound to be aromatic, the value of n must be an integer (n = 0, 1, 2...). Since the value of n is not an integer, the given compound is not aromatic in nature.
- #12-i
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Ans :
For the given compound, the number of ``\pi``-electrons is six. But only four ``\pi``-electrons are present within the ring. Also there is no conjugation of``\pi``-electrons within the ring and the compound is not planar in shape. Hence, the given compound is not aromatic in nature.
()
For the given compound, the number of ``\pi``-electrons is four.
By Huckel’s rule,
4n + 2 = 4
4n = 2
For a compound to be aromatic, the value of n must be an integer (n = 0, 1, 2...), which is not true for the given compound. Hence, it is not aromatic in nature.
()
For the given compound, the number of ``\pi``-electrons is eight.
By Huckel’s rule,
4n + 2 = 8
4n = 6
For a compound to be aromatic, the value of n must be an integer (n = 0, 1, 2...). Since the value of n is not an integer, the given compound is not aromatic in nature.
- #12-ii
Ans :
For the given compound, the number of ``\pi``-electrons is four.
By Huckel’s rule,
4n + 2 = 4
4n = 2
For a compound to be aromatic, the value of n must be an integer (n = 0, 1, 2...), which is not true for the given compound. Hence, it is not aromatic in nature.
- #12-iii
Ans :
For the given compound, the number of ``\pi``-electrons is eight.
By Huckel’s rule,
4n + 2 = 8
4n = 6
For a compound to be aromatic, the value of n must be an integer (n = 0, 1, 2...). Since the value of n is not an integer, the given compound is not aromatic in nature.