NEET-XI-Chemistry
06: Chemical Thermodynamics
- #7In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?
Ans : According to the first law of thermodynamics,
ΔU = q + W (i)
Where,
ΔU = change in internal energy for a process
q = heat
W = work
Given,
q = + 701 J (Since heat is absorbed)
W = -394 J (Since work is done by the system)
Substituting the values in expression (i), we get
ΔU = 701 J + (-394 J)
ΔU = 307 J
Hence, the change in internal energy for the given process is 307 J.