NEET-XI-Chemistry

01: Some Basic Concepts of Chemistry

  • #4
    Calculate the amount of carbon dioxide that could be produced when
    () 1 mole of carbon is burnt in air.
    () 1 mole of carbon is burnt in 16 g of dioxygen.
    () 2 moles of carbon are burnt in 16 g of dioxygen.
    () 1 mole of carbon is burnt in air.
    () 1 mole of carbon is burnt in 16 g of dioxygen.
    () 2 moles of carbon are burnt in 16 g of dioxygen.
    Ans : The balanced reaction of combustion of carbon can be written as:


    () As per the balanced equation, 1 mole of carbon burns in1 mole of dioxygen (air) to produce1 mole of carbon dioxide.
    () According to the question, only 16 g of dioxygen is available. Hence, it will react with 0.5 mole of carbon to give 22 g of carbon dioxide. Hence, it is a limiting reactant.
    () According to the question, only 16 g of dioxygen is available. It is a limiting reactant. Thus, 16 g of dioxygen can combine with only 0.5 mole of carbon to give 22 g of carbon dioxide.
    () As per the balanced equation, 1 mole of carbon burns in1 mole of dioxygen (air) to produce1 mole of carbon dioxide.
    () According to the question, only 16 g of dioxygen is available. Hence, it will react with 0.5 mole of carbon to give 22 g of carbon dioxide. Hence, it is a limiting reactant.
    () According to the question, only 16 g of dioxygen is available. It is a limiting reactant. Thus, 16 g of dioxygen can combine with only 0.5 mole of carbon to give 22 g of carbon dioxide.
  • #4-i
    1 mole of carbon is burnt in air.
    Ans : As per the balanced equation, 1 mole of carbon burns in1 mole of dioxygen (air) to produce1 mole of carbon dioxide.
  • #4-ii
    1 mole of carbon is burnt in 16 g of dioxygen.
    Ans : According to the question, only 16 g of dioxygen is available. Hence, it will react with 0.5 mole of carbon to give 22 g of carbon dioxide. Hence, it is a limiting reactant.
  • #4-iii
    2 moles of carbon are burnt in 16 g of dioxygen.
    Ans : According to the question, only 16 g of dioxygen is available. It is a limiting reactant. Thus, 16 g of dioxygen can combine with only 0.5 mole of carbon to give 22 g of carbon dioxide.