Qstnid -A-1- Find The Area Of A Triangle, Whose Sides Are : (I) 10 Cm, 24 Cm And 26 Cm (Ii) 18 Mm, 24 Mm And 30 Mm (Iii) 21 M, 28 M And 35 M (I) 10 Cm, 24 Cm And 26 Cm (Ii) 18 Mm, 24 Mm And 30 Mm (Iii) 21 M, 28 M And 35 M - 20: Area Of Trapezium And A Polygon Class 8 Maths - Icse-viii-mathematics

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ICSE-VIII-Mathematics

20: Area of Trapezium and a Polygon Class 8 Maths

with Solutions -

Qstn# A-1 Prvs-Qstn Next-Qstn

#1
Find the area of a triangle, whose sides are : (i) 10 cm, 24 cm and 26 cm (ii) 18 mm, 24 mm and 30 mm (iii) 21 m, 28 m and 35 m (i) 10 cm, 24 cm and 26 cm (ii) 18 mm, 24 mm and 30 mm (iii) 21 m, 28 m and 35 m
Ans : (i) Sides of ∆ are
a = 10 cm
b = 24 cm
c = 26 cm
S = (a + b + c)/2 = (10 + 24 + 26)/2
= 60/2
= 30
(ii) Sides of ∆ are
a = 18 mm
b = 24 mm
c = 30 mm
S = (a + b + c)/2
= (18 + 24 + 30)/2
= 72/2
= 36
(iii) Sides of ∆ are
a = 21 m
b = 28 m
c = 35 m
S = (a + b + c)/2
= (21 + 28 + 35)/2
= 84/2
= 42
(i) Sides of ∆ are
a = 10 cm
b = 24 cm
c = 26 cm
S = (a + b + c)/2 = (10 + 24 + 26)/2
= 60/2
= 30
(ii) Sides of ∆ are
a = 18 mm
b = 24 mm
c = 30 mm
S = (a + b + c)/2
= (18 + 24 + 30)/2
= 72/2
= 36
(iii) Sides of ∆ are
a = 21 m
b = 28 m
c = 35 m
S = (a + b + c)/2
= (21 + 28 + 35)/2
= 84/2
= 42

#1-i
10 cm, 24 cm and 26 cm
Ans : Sides of ∆ are
a = 10 cm
b = 24 cm
c = 26 cm
S = (a + b + c)/2 = (10 + 24 + 26)/2
= 60/2
= 30

#1-ii
18 mm, 24 mm and 30 mm
Ans : Sides of ∆ are
a = 18 mm
b = 24 mm
c = 30 mm
S = (a + b + c)/2
= (18 + 24 + 30)/2
= 72/2
= 36

#1-iii
21 m, 28 m and 35 m
Ans : Sides of ∆ are
a = 21 m
b = 28 m
c = 35 m
S = (a + b + c)/2
= (21 + 28 + 35)/2
= 84/2
= 42