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ICSE-VIII-Mathematics

20: Area of Trapezium and a Polygon Class 8 Maths

with Solutions - page 5
Qstn# C-4 Prvs-QstnNext-Qstn
  • #4
    A parallelogram has sides of 15 cm and 12 cm; if the distance between the 15 cm sides is 6 cm; find the distance between 12 cm sides.
    Ans : Base, AB = 15 cm
    Distance between 15 cm sides
    i.e., height DP = 6 cm
    ∴ Area of ∥gm = Base × Height
    = AB × DP
    = 15 × 6
    = 90 cm2
    Let BQ be distance 12 cm sides
    ∴ AD × BQ = area of ∥gm ABCD
    ∴ 12 × BQ = 90
    BQ = 90/12
    BQ = 15/2
    = 7.5 cm