ICSE-VIII-Mathematics

17: Special Types of Quadrilaterals Class 8 Maths

with Solutions -
  • #1
    In parallelogram ABCD, ∠A = 3 times ∠B. Find all the angles of the parallelogram. In the same parallelogram, if AB = 5x - 7 and CD = 3x + 1 ; find the length of CD.
    Ans :
    Let ∠B = x
    ∠A = 3 ∠B = 3x
    AD || BC
    ∠A + ∠B = 180°
    3x + x = 180°
    ⇒ 4x = 180°
    ⇒ x = 45°
    ∠B = 45°
    ∠A = 3x = 3 x 45 = 135°
    and ∠B = ∠D = 45°
    opposite angles of ||gm are equal.
    ∠A = ∠C = 135°
    opposite sides of //gm are equal.
    AB = CD
    5x - 7 = 3x + 1
    ⇒ 5x - 3x = 1+7
    ⇒ 2x = 8
    ⇒ x = 4°
    CD = 3 x 4 + 1 = 13
    Hence, 135°, 45°, 135° and 45°; 13