ICSE-VIII-Mathematics

16: Understanding Shapes (Including Polygons) Class 8 Maths

with Solutions - page 6
  • #5
    In quadrilateral ABCD, side AB is parallel to side DC. If ∠A : ∠D = 1 : 2 and ∠C : ∠B = 4 : 5 (i) Calculate each angle of the quadrilateral. (ii) Assign a special name to quadrilateral ABCD
    Ans :
    ∵ ∠A : ∠D = 1 : 2
    Let ∠A = x and ∠B = 2x
    ∵ ∠C : ∠B = 4 : 5
    Let ∠C = 4y and ∠B = 5y
    ∵ AB ∥ DC
    ∴ ∠A + ∠D = 180˚
    x + 2x = 180˚
    ⇒ 3x = 180˚
    ⇒ x = 60˚
    ∴ A = 60˚
    ∠D = 2x = 2 × 60˚ = 120˚
    Again ∠B + ∠C = 180˚
    5y + 4y = 180˚
    ⇒ 9y = 180˚
    ⇒ y = 20˚
    ∴ ∠B = 5y = 5 × 20˚ = 100˚
    ∠C = 4y = 4 × 20˚ = 80˚
    Hence ∠A = 60˚ : ∠B = 100˚ : ∠C = 80˚ ∠D = 120˚
    (iii) Quadrilateral ABCD is a trapezium because one pair of opposite side is parallel.