ICSE-VIII-Mathematics

14: Linear Equations in one Variable Class 8 Maths

with Solutions -
Qstn# A-14 Prvs-QstnNext-Qstn
  • #14
    (a + 5)/6 - (a + 1)/9 = (a + 3)/4
    Ans : Since L.C.M. of denominators 6, 9 and 4 = 36
    ∴ (a + 5)/6 × 36 - (a + 1)/9 × 36 = (a + 3)/4 × 36
    (Multiplying each term by 36)
    ⇒ 6(a + 5) - 4(a + 1) = 9(a + 3)
    ⇒ 6a + 30 - 4a - 4 = 9a + 27
    ⇒ 6a - 4a - 9a = 27 - 30 + 4
    ⇒ 6a - 13a = 1
    ⇒ -7a = 1
    ⇒ a = - 1/7