Qstnid -Ii-12-a Conducting Square Loop Of Side L And Resistance R Moves In Its Plane With A Uniform Velocity V Perpendicular To One Of Its Sides. A Uniform And Constant Magnetic Field B Exists Along The Perpendicular To The Plane Of The Loop As Shown In Figure. The Current Induced In The Loop Is - 38: Electromagnetic Induction - Cbse-xi-physics

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CBSE-XI-Physics

38: Electromagnetic Induction

with Solutions - page 2

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#12
A conducting square loop of side l and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A uniform and constant magnetic field B exists along the perpendicular to the plane of the loop as shown in figure. The current induced in the loop is
(a) Blv/R clockwise
(b) Blv/R anticlockwise
(c) 2Blv/R anticlockwise
(d) zero.
Figure
digAnsr: d
Ans : (d) zero

Figure
(a) shows the square loop moving in its plane with a uniform velocity v.
Figure
(b) shows the equivalent circuit.
The induced emf across ends AB and CD is given by
`` E=Bvl``
On applying KVL in the equivalent circuit, we get
`` E-E+iR=0``
`` \Rightarrow i=0``
No current will be induced in the circuit due to zero potential difference between the closed ends.
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