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CBSE-XI-Physics

34: Magnetic Field

with Solutions -
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  • #5
    Which of the following particles will have minimum frequency of revolution when projected with the same velocity perpendicular to a magnetic field?
    (a) Electron
    (b) Proton
    (c) He+
    (d) Li+
    digAnsr:   d
    Ans :
    (d) Li    +
    Time period of the revolution of the particle, `` T=\frac{2\,\mathrm{\,\pi \,}m}{qB}``
    As frequency is the reciprocal of time period, so `` f=\frac{qB}{2\,\mathrm{\,\pi \,}m}``
    The charge on all the four particles is same. But the mass is maximum for Li+. So, it will have the smallest frequency of revolution.
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