CBSE-XI-Physics

31: Capacitors

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  • #5
    A dielectric slab is inserted between the plates of an isolated capacitor. The force between the plates will
    (a) increase
    (b) decrease
    (c) remain unchanged
    (d) become zero.
    digAnsr:   c
    Ans : (c) remain unchanged
    The force between the plates is given by
    F = `` \frac{{q}^{2}}{2{\in }_{0}A}``
    Since the capacitor is isolated, the charge on the plates remains constant.
    We know that the charge is conserved in an isolated system.
    Thus, the force acting between the plates remains unchanged.
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