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CBSE-XI-Physics

05: Newton's Laws of Motion

with Solutions - page 6
Qstn# iv-29 Prvs-QstnNext-Qstn
  • #29
    In the previous problem, suppose m2 = 2.0 kg and m3 = 3.0 kg. What should be the mass m, so that it remains at rest?
    Ans :
    For m1 to be at rest, a1 = 0.
    T - m1g = 0
    T = m1g ...(i)
    For mass m2,
    T/2 - 2g = 2a
    T = 4a + 4g ...(ii)
    For mass m3,
    3g - T/2= 2a
    T = 6g - 6a ...(ii)
    From equations (ii) and (iii), we get:
    3T - 12g = 12g - 2T
    T = 24g/5= 4.08g
    Putting the value of T in equation (i), we get:
    m1 = 4.8kg
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