CBSE-XI-Physics
05: Newton's Laws of Motion
- #13The elevator shown in figure (5-E5) is descending with an acceleration of 2 m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B?
Figure
Ans : When the elevator is descending, a pseudo-force acts on it in the upward direction, as shown in the figure.
From the free-body diagram of block A,
`` mg-N=ma``
`` N=m\left(g-a\right)``
`` \Rightarrow N=0.5\left(10-2\right)=4\,\mathrm{\,N \,}``
`` ``
So, the force exerted by the block A on the block B is 4 N.
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