CBSE-XI-Physics

05: Newton's Laws of Motion

with Solutions - page 5
Qstn# iv-10 Prvs-QstnNext-Qstn
  • #10
    Both the springs shown in figure (5-E2) are unstretched. If the block is displaced by a distance x and released, what will be the initial acceleration?
    Figure
    Ans : Let the block m be displaced towards left by displacement x.

    ∴ F1 = `` -``k1x (compressed)
    F2 = `` -``k2x (expanded)
    `` ma={F}_{1}+{F}_{2}``
    `` \Rightarrow a=\frac{-x\left({k}_{1}+{k}_{2}\right)}{m}``
    i.e. `` \left({k}_{1}+{k}_{2}\right)\frac{x}{m}`` opposite the displacement or towards the mean position.
    Page No 79: