CBSE-XI-Physics
05: Newton's Laws of Motion
- #9A particle of mass 0.3 kg is subjected to a force F = -kx with k = 15 N/m. What will be its initial acceleration if it is released from a point x = 20 cm?Ans : Displacement of the particle from the mean position, x = 20 cm = 0.2 m
k = 15 N/m
Mass of the particle, m = 0.3 kg
Acceleration, `` a=\frac{\left|\mathit{F}\right|}{m}``
`` \Rightarrow a=\frac{kx}{m}=\frac{15\left(0.2\right)}{0.3}=\frac{3}{0.3}=10\,\mathrm{\,m \,}/{\,\mathrm{\,s \,}}^{2}``
So, the initial acceleration when the particle is released from a point x = 20 cm is 10 m/s2.
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