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NEET-XII-Chemistry
09: Coordination Compounds
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page 2
Qstn# II-9-i
Prvs-Qstn
Next-Qstn
#9-i
[Cr(C
2
O
4
)
3
]
3-
(ii) [Co(NH
3
)
3
Cl
3
]
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Ans
:
For [Cr(C
2
O
4
)
3
]
3-
, no geometric isomer is possible as it is a bidentate ligand.
(ii) [Co(NH
3
)
3
Cl
3
]
Two geometrical isomers are possible.
+