NEET-XII-Chemistry
04: Chemical Kinetics
- #1-i3 NO(g) → N2O (g) Rate = k[NO]2
() H2O2 (aq) + 3 I- (aq) + 2 H+ → 2 H2O (l) +
Rate = k[H2O2][I-]
() CH3CHO(g) → CH4(g) + CO(g) Rate = k [CH3CHO]3/2
() C2H5Cl(g) → C2H4(g) + HCl(g) Rate = k [C2H5Cl]
() H2O2 (aq) + 3 I- (aq) + 2 H+ → 2 H2O (l) +
Rate = k[H2O2][I-]
() CH3CHO(g) → CH4(g) + CO(g) Rate = k [CH3CHO]3/2
() C2H5Cl(g) → C2H4(g) + HCl(g) Rate = k [C2H5Cl]
() H2O2 (aq) + 3 I- (aq) + 2 H+ → 2 H2O (l) +
Rate = k[H2O2][I-]
() CH3CHO(g) → CH4(g) + CO(g) Rate = k [CH3CHO]3/2
() C2H5Cl(g) → C2H4(g) + HCl(g) Rate = k [C2H5Cl]Ans : Given rate = k [NO]2
Therefore, order of the reaction = 2
Dimension of

() Given rate = k [H2O2] [I-]
Therefore, order of the reaction = 2
Dimension of

() Given rate = k [CH3CHO]3/2
Therefore, order of reaction =
Dimension of

() Given rate = k [C2H5Cl]
Therefore, order of the reaction = 1
Dimension of

() Given rate = k [H2O2] [I-]
Therefore, order of the reaction = 2
Dimension of

() Given rate = k [CH3CHO]3/2
Therefore, order of reaction =
Dimension of

() Given rate = k [C2H5Cl]
Therefore, order of the reaction = 1
Dimension of

() Given rate = k [H2O2] [I-]
Therefore, order of the reaction = 2
Dimension of

() Given rate = k [CH3CHO]3/2
Therefore, order of reaction =
Dimension of

() Given rate = k [C2H5Cl]
Therefore, order of the reaction = 1
Dimension of

- #1-iiH2O2 (aq) + 3 I- (aq) + 2 H+ → 2 H2O (l) +
Rate = k[H2O2][I-]Ans : Given rate = k [H2O2] [I-]
Therefore, order of the reaction = 2
Dimension of

- #1-iiiCH3CHO(g) → CH4(g) + CO(g) Rate = k [CH3CHO]3/2Ans : Given rate = k [CH3CHO]3/2
Therefore, order of reaction =
Dimension of

- #1-ivC2H5Cl(g) → C2H4(g) + HCl(g) Rate = k [C2H5Cl]Ans : Given rate = k [C2H5Cl]
Therefore, order of the reaction = 1
Dimension of
