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NEET-XII-Chemistry

02: Solutions

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  • #7
    Henry’s
    law constant for CO2 in water is 1.67 × 108 Pa at 298 K. Calculate the quantity of CO2 in 500 mL of soda water when packed under 2.5 atm CO2 pressure at 298 K.
    Ans : It
    is given that:
    KH = 1.67 × 108 Pa
    = 2.5 atm = 2.5 × 1.01325 × 105 Pa
    =
    2.533125 × 105 Pa
    According
    to Henry’s law:

    = 0.00152
    We
    can write,
    [Since, is
    negligible as compared to]
    In
    500 mL of soda water, the volume of water =
    500 mL
    [Neglecting
    the amount of soda present]
    We can
    write:
    500 mL of
    water = 500 g of water

    = 27.78 mol of water
    Now,


    Hence,
    quantity of CO2 in 500 mL of soda water = (0.042 × 44)g
    = 1.848 g
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