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NEET-XII-Chemistry

02: Solutions

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  • #6
    H2S,
    a toxic gas with rotten egg like smell, is used for the qualitative
    analysis. If the solubility of H2S
    in water at STP is 0.195 m, calculate Henry’s law constant.
    Ans : It
    is given that the solubility of H2S
    in water at STP is 0.195 m, i.e., 0.195 mol of H2S
    is dissolved in 1000 g of water.
    Moles
    of water
    = 55.56
    mol
    ∴Mole
    fraction of H2S, x

    = 0.0035
    At
    STP, pressure (p)
    = 0.987 bar
    According
    to Henry’s law:
    p = KHx

    = 282
    bar