Loading…
NEET-XII-Chemistry

02: Solutions

with Solutions - page 4
Qstn# B-39 Prvs-QstnNext-Qstn
  • #39
    The air is
    a mixture of a number of gases. The major components are oxygen
    and
    nitrogen with approximate proportion of 20% is to 79% by volume at
    298
    K.
    The water is in equilibrium with air at a pressure of 10 atm. At 298
    Kif the
    Henry’s
    law constants for oxygen and nitrogen are 3.30 × 107 mm and 6.51 × 107 mm respectively, calculate the composition of these gases in water.
    Ans : Percentage
    of oxygen (O2)
    in air = 20 %
    Percentage
    of nitrogen (N2)
    in air = 79%
    Also, it
    is given that water is in equilibrium with air at a total pressure of
    10 atm, that is, (10 × 760) mm Hg = 7600 mm Hg
    Therefore,
    Partial
    pressure of oxygen,
    = 1520
    mm Hg
    Partial
    pressure of nitrogen,
    =
    6004 mmHg
    Now,
    according to Henry’s law:
    p = KH.x
    For
    oxygen:

    For
    nitrogen:

    Hence,
    the mole fractions of oxygen and nitrogen in water are 4.61 ×10-5and
    9.22 × 10-5 respectively.