NEET-XII-Physics
neet 2020 questions with solutions year:2020
- #20The mean free path for a gas, with molecular diameter `` d `` and number density `` n `` can be expressed as :
(A) `` \frac {1}{\sqrt{2} n \pi d} ``
(B) `` \frac {1}{\sqrt{2} n \pi d^2} ``
(C) `` \frac {1}{\sqrt{2} n^2 \pi d^2} ``
(D) `` \frac {1}{\sqrt{2} n^2 \pi^2 d^2} ``
digAnsr: BAns : Mean free path for a gas sample `` \lambda_{m}=\frac{1}{\sqrt{2}\pi d^{2} n} ``
where d is diameter of a gas molecule and n is molecular density