NEET-XII-Chemistry
Previous Year Paper year:2017
- #14Pick out the correct statement with respect to ``[Mn(CN)_6]^{3-}`` :
(1) It is ``dsp^2`` hybridised and square planar
(2) It is ``sp^3d^2`` hybridised and octahedral
(3) It is ``sp^3d^2`` hybridised and tetrahedral
(4) It is ``d^2sp^3`` hybridised and octahedraldigAnsr: 4Ans : (4)
Sol. [Mn(CN)6]-3
25Mn = [Ar] 3d54s2
Mn+3 = [Ar] 3d4
CN- is strong ligand
∴ Δ0 is high complex is d2sp3 hybridised and inner octahedral
d2 sp3
inner octahedral
n = 2