NEET-XI-Physics
exam-2 year:2016
- #130The temperature inside a refrigerator is ``t_2`` °C and
the room temperature is ``t_1``°C. The amount of heat
delivered to the room for each joule of electrical
energy consumed ideally will be :-
(1)``\frac{t_2 + 273}{t_1 - t_2}``
(2) ``\frac{t_1 + t_2}{t_1 + 273}``
(3) ``\frac{t_1 }{t_1 - t_2}``
(4)``\frac{t_1 + 273}{t_1 - t_2}``digAnsr: 4Ans : (4)
Sol. Heat delivered = Q1
COP() =
2 1 1 2
1 2
Q Q W Q T
1
W W W T T
= = =
&implies;
1 2
1 2
Q t 273
1
W t t
+
= +
1
1 2
t 273
t t
+
=