NEET-XI-Physics

exam-2 year:2016

with Solutions - page 3
  • #114
    Two cars P and Q start from a point at the same
    time in a straight line and their positions are
    represented by ``x_p(t) = at + bt^2`` and ``x_Q (t) = ft - t^2``.
    At what time do the cars have the same velocity ?
    (1)``\frac {a+ f}{2(1+ b)}``
    (2)``\frac { f -a}{2(1+ b)}``
    (3)``\frac {a- f}{(1+ b)}``
    (4)``\frac {a+ f}{2(b - 1)}``
    digAnsr:   2
    Ans : (2)
    Sol. xP(t) = at + bt2 xQ(t) = ft - t2
    vP = a + 2bt vQ = f - 2t
    as vP = vQ
    a + 2bt = f - 2t
    &implies;
    f a
    t
    2(1 b)
    
    =
    +