NEET-XI-Physics
exam-2 year:2016
- #114Two cars P and Q start from a point at the same
time in a straight line and their positions are
represented by ``x_p(t) = at + bt^2`` and ``x_Q (t) = ft - t^2``.
At what time do the cars have the same velocity ?
(1)``\frac {a+ f}{2(1+ b)}``
(2)``\frac { f -a}{2(1+ b)}``
(3)``\frac {a- f}{(1+ b)}``
(4)``\frac {a+ f}{2(b - 1)}``digAnsr: 2Ans : (2)
Sol. xP(t) = at + bt2 xQ(t) = ft - t2
vP = a + 2bt vQ = f - 2t
as vP = vQ
a + 2bt = f - 2t
&implies;
f a
t
2(1 b)
ï€
=
+