ICSE-X-Physics

Previous Year Paper year:2019

with Solutions - page 5
 
  • #6
  • #6-a
    How does the angle of deviation formed by a prism change with the increase in the angle of

    incidence? Draw a graph showing the variation in the angle of deviation with the angle of incidence at a prism surface.

    [3]
    Ans : As the. angle of incidence increases the angle of deviation decreases becomes minimum and then increases.

    The graph is as shown :




  • #6-b
    A virtual, diminished image is formed when an object is placed between the optical centre and the principal focus of a lens.
  • #6-b-i
    Name the type of lens which forms the above image.
    Ans : Concave lens.
  • #6-b-ii
    Draw a ray diagram to show the formation of the image with the above stated characteristics.

    [3]
    Ans : The ray diagram is as shown :




  • #6-c
    An object is placed at a distance 24 cm in front of a convex lens of focal length 8 cm.
    Ans : Given u = - 24 cm, f= + 8 cm, v = ?
  • #6-c-i
    What is the nature of the image so formed ?
    Ans : Real, inverted and diminished.
  • #6-c-ii
    Calculate the distance of the image from the lens.
    Ans : Using the lens formula

    ``\frac { v }{ u }`` = ``\frac { 12 }{ -24 }`` = ``\frac { 1 }{ 2 }`` .


  • #6-c-iii
    Calculate the magnification of the image.

    [4]
  • #7
  • #7-a
    It is observed that during march-past we hear a base drum distinctly from a distance compared to the side drums.
  • #7-a-i
    Name the characteristic of sound associated with the above observation.
    Ans : Intensity of sound.
  • #7-a-ii
    Give a reason for the above observation.

    [3]
    Ans : This is because the amplitude of vibration of a base drum is far greater than the amplitude of vibration of the side drum.



    (b) Given f= 4 vbs, T = ``\frac { 1 }{ f }`` = ``\frac { 1 }{ 4 }`` = 0.25 s, for a frequency of 6 vbs titme t= ``\frac { 0.25 }{ 4 }`` x 6 = 0.375 s, ,V=340ms-1

    Using S = ``\frac{\mathbf{V} \times t}{2}`` = ``\frac{340 \times 0.375}{2}`` = 63.75 m



    (c) (i) Free or natural oscillation.

    (ii) Forced oscillation.

    (iii) The amplitude of the oscillation of D will be equal to the amplitude of the oscillation of C.

    (iv) Resonance.


  • #7-b
    A pendulum has a frequency of 4 vibrations per second. An observer starts the pendulum and fires a gun simultaneously. He hears the echo from the cliff after 6 vibrations of the pendulum. If the velocity of sound in air is 340 m s1, find the distance between the cliff and the observer.

    [3]
  • #7-c
    Two pendulums C and D are suspended from a wire as shown in the given figure. Pendulum C is made to oscillate by displacing it from its mean position. It is seen that D also starts oscillating.