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CBSE-IX-Science

03: 2-Forces and Laws of Motion

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  • #6
    A stone of 1 kg is thrown with a velocity of across the frozen surface of a lake and comes to rest after travelling a distance of 50 m. What is the force of friction between the stone and the ice?
    Ans : since

    (object comes to rest so v=0)

    -100a = 400

    a = 400/-100 =

    therefore, the force of friction between the stone and the ice

    = -4 N