NEET-XII-Physics
22: Photometry
- #1A source emits 45 joules of energy in 15 s. What is the radiant flux of the source?Ans : Given,
Total energy emitted (E) = 45 J
Time (t) = 15 s
Radiant flux of the source is given by,
`` \,\mathrm{\,Radiant\,}\,\mathrm{\,Flux\,}=\frac{\,\mathrm{\,Total\,}\,\mathrm{\,energy\,}\,\mathrm{\,emitted\,}}{\,\mathrm{\,Time\,}}``
`` =\frac{45}{15}=3\,\mathrm{\,W\,}``
So, the radiant flux of the source is 3 W.
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