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NEET-XII-Physics

22: Photometry

with Solutions - page 2
Qstn# iv-4 Prvs-QstnNext-Qstn
  • #4
    The relative luminosity of wavelength 600 nm is 0.6. Find the radiant flux of 600 nm needed to produce the same brightness sensation as produced by 120 W of radiant flux at 555 nm.
    Ans : Given,
    Relative luminosity = 0.6
    Let P be the radiant flux of the source.
    ∴ Luminous flux = P`` \times ``685
    Again, relative luminosity`` =\frac{\,\mathrm{\,Luminous\,}\,\mathrm{\,flux\,}\,\mathrm{\,of\,}\,\mathrm{\,a\,}\,\mathrm{\,source\,}\,\mathrm{\,of\,}\,\mathrm{\,given\,}\,\mathrm{\,wavelength\,}}{\,\mathrm{\,Luminous\,}\,\mathrm{\,flux\,}\,\mathrm{\,of\,}\,\mathrm{\,a\,}\,\mathrm{\,source\,}\,\mathrm{\,of\,}555\,\mathrm{\,nm\,}\,\mathrm{\,of\,}\,\mathrm{\,same\,}\,\mathrm{\,power\,}}``
    `` ``
    `` \therefore 0.6=\frac{\,\mathrm{\,Luminous\,}\,\mathrm{\,flux\,}\,\mathrm{\,of\,}\,\mathrm{\,a\,}\,\mathrm{\,source\,}P\,\mathrm{\,watt\,}}{685P}``
    `` \Rightarrow 685\times P\times 0.6=120\times 685``
    `` \Rightarrow \,\mathrm{\,P\,}=\frac{120}{0.6}=200\,\mathrm{\,W\,}``
    So, 200 W radiant flux is needed to produce the same brightness sensation for 600 nm wavelength.
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