NEET-XII-Physics

12: Simple Harmonic Motion

with Solutions - page 2
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  • #1
    A student says that he had applied a force
    F=-kxon a particle and the particle moved in simple harmonic motion. He refuses to tell whether k is a constant or not. Assume that he was worked only with positive x and no other force acted on the particle.
    (a) As x increases k increases.
    (b) As x increases k decreases.
    (c) As x increases k remains constant.
    (d) The motion cannot be simple harmonic.
    digAnsr:   a
    Ans : (a) As x increases k increases.
    A body is said to be in simple harmonic motion only when,
    F = `` -`` kx ...(1)
    where F is force,
    k is force constant, and
    x is displacement of the body from the mean position.
    Given:
    F = -k`` \sqrt{x}`` ...(2)


    On comparing the equations (1) and (2), it can be said that in order to execute simple harmonic motion, k should be proportional to `` \sqrt{x}`` . Thus, as x increases k increases.
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