NEET-XII-Physics
11: Gravitation
- #36Find the minimum colatitude which can directly receive a signal from a geostationary satellite.Ans : Consider that B is the position of the geostationary satellite.
In the given figure, `` \varphi `` is the latitude and θ is the colatitude of a place which can directly receive a signal from a geostationary satellite.
In triangle OAB, we have:
`` \,\mathrm{\,cos\,}\,\mathrm{\,\varphi \,}=\frac{6400}{42000}``
`` =\frac{16}{106}=\frac{8}{53}``
`` \,\mathrm{\,i\,}.\,\mathrm{\,e\,}.,\,\mathrm{\,\varphi \,}={\,\mathrm{\,cos\,}}^{-1}\frac{8}{53}``
`` ={\,\mathrm{\,cos\,}}^{-1}0.15``
`` \,\mathrm{\,Now\,},\theta =\frac{\pi }{2}-\varphi ``
`` \Rightarrow \theta =\frac{\pi }{2}-{\,\mathrm{\,cos\,}}^{-1}0.15``
`` \Rightarrow \theta ={\,\mathrm{\,sin\,}}^{-1}0.15``
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