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NEET-XII-Physics

10: Rotational Mechanics

with Solutions - page 2
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  • #5
    Figure (10-Q3) shows a small wheel fixed coaxially on a bigger one of double the radius. The system rotates about the common axis. The strings supporting A and B do not slip on the wheels. If x and y be the distance travelled by A and B in the same time interval, then
    (a) x = 2 y
    (b) x = y
    (c) y = 2 x
    (d) none of these.
    Figure
    digAnsr:   c
    Ans : (c) y = 2 x
    It is given that angular velocity is same for both the wheels.
    Therefore, we have:
    vA = `` \omega ``R
    vB = `` \omega ``2R
    x = vAt = `` \omega ``Rt ... (i)
    y = vBt = `` \omega ``(2R)t ... (ii)
    From equations (i) and (ii), we get:
    y = 2 x
    Page No 193: