NEET-XII-Physics
07: Circular Motion
- #7If the road of the previous problem is horizontal (no banking), what should be the minimum friction coefficient so that scooter going at 18 km/hr does not skid?Ans : If the road is horizontal (no banking), we have:
`` \frac{m{v}^{2}}{R}={f}_{s}``
`` N=mg``
`` ``
Here, fs is the force of friction and N is the normal reaction.
If μ is the friction coefficient, we have:
`` \,\mathrm{\,Friction \,}\,\mathrm{\,force \,}={f}_{s}=\mu N``
`` \,\mathrm{\,So \,},\frac{m{v}^{2}}{R}=\mu mg``
Here,
Velocity = v = 5 m/s
Radius = R = 10 m
`` \therefore \frac{25}{10}=\mu g``
`` \Rightarrow \mu =\left(\frac{25}{100}\right)=0.25``
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