NEET-XII-Physics
07: Circular Motion
- #5If the horizontal force needed for the turn in the previous problem is to be supplied by the normal force by the road, what should be the proper angle of banking?Ans : Given:
Speed of the scooter = v = 36 km/hr = 10 m/s
Radius of turn = r = 30 m
Let the angle of banking be `` \theta ``. We have:
`` \,\mathrm{\,tan \,}\theta =\frac{{v}^{2}}{rg}``
`` \Rightarrow \,\mathrm{\,tan \,}\theta =\frac{100}{30\times 10}=\frac{1}{3}``
`` \Rightarrow \theta ={\,\mathrm{\,tan \,}}^{-1}\left(\frac{1}{3}\right)``
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