NEET-XII-Physics
04: The Forces
- #6A body builder exerts a force of 150 N against a bullworker and compresses it by 20 cm. Calculate the spring constant of the spring in the bullworker.Ans : Force exerted by the body builder against the bullworker = 150 N
Compression in the bullworker, x = 20 cm = 0.2 m
∴ Total force exerted, f = kx = 150
Here, k is the spring constant of the spring in the bullworker.
`` \therefore k=\frac{150}{0.2}=\frac{1500}{2}=750\,\mathrm{\,N \,}/\,\mathrm{\,m \,}``
Hence, the spring constant of the spring in the bullworker is 750 N/m.