Qstnid -Iv-5-a Monkey Is Sitting On A Tree Limb. The Limb Exerts A Normal Force Of 48 N And A Frictional Force Of 20 N. Find The Magnitude Of The Total Force Exerted By The Limb On The Monkey. - 04: The Forces - Neet-xii-physics

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NEET-XII-Physics

04: The Forces

with Solutions - page 2

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#5
A monkey is sitting on a tree limb. The limb exerts a normal force of 48 N and a frictional force of 20 N. Find the magnitude of the total force exerted by the limb on the monkey.
Ans : Given: The limb of the tree exerts a normal force of 48 N and a frictional force of 20 N.

So, resultant magnitude of the force if given by
`` R=\sqrt{\left({48}^{2}+{20}^{2}\right)}``
`` =\sqrt{2304+400}``
`` =\sqrt{2704}=52\,\mathrm{\,N \,}``
∴ The magnitude of the total force exerted by the limb on the monkey is 52 N.