NEET-XII-Physics
01: Introduction to Physics
- #6∫dx2ax-x2=ansin-1xa-1.
The value of n is
-(a) 0
(b) -1
(c) 1
(d) none of these.
You may use dimensional analysis to solve the problem.digAnsr: aAns : (a) 0
[ax] = [x2]
⇒ [a] = [x] ...(1)
Dimension of LHS = Dimension of RHS
`` \Rightarrow \left[\frac{dx}{\sqrt{{x}^{2}}}\right]=\left[{a}^{n}\right]\phantom{\rule{0ex}{0ex}}\Rightarrow \left[\frac{L}{L}\right]=\left[{a}^{n}\right]...\left(2\right)\phantom{\rule{0ex}{0ex}}\left[{L}^{0}\right]=\left[{a}^{n}\right]\phantom{\rule{0ex}{0ex}}n=0\phantom{\rule{0ex}{0ex}}``