Qstnid -Iv-26-the Half-life Of A Radioisotope Is 10 H. Find The Total Number Of Disintegration In The Tenth Hour Measured From A Time When The Activity Was 1 Ci. - 46: The Nucleus - Neet-xii-physics

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NEET-XII-Physics

46: The Nucleus

with Solutions - page 7

Qstn# iv-26 Prvs-Qstn Next-Qstn

#26
The half-life of a radioisotope is 10 h. Find the total number of disintegration in the tenth hour measured from a time when the activity was 1 Ci.
Ans : Given:
Half-life of radioisotope, `` {T}_{1/2}`` = 10 hrs
Initial activity, A₀ = 1 Ci
Disintegration constant, `` \lambda =\frac{0.693}{10\times 3600}{\,\mathrm{\,s\,}}^{-1}``
Activity of radioactive sample, `` A={A}_{0}{e}^{-\lambda t}``
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