NEET-XII-Physics
46: The Nucleus
- #3Calculate the mass of an α-particle. Its Its binding energy is 28.2 MeV.Ans : Given:
Binding energy of α particle = 28.2 MeV
Let x be the mass of α particle.
We know an α particle consists of 2 protons and 2 neutrons.
Binding energy, `` B=\left(Z{m}_{p}+N{m}_{n}-M\right){c}^{2}``
`` ``
Here, mp = Mass of proton
mn = Mass of neutron
Z= Number of protons
N = Number of neutrons
c = Speed of light
On substituting the respective values, we have
`` 28.2=(2\times 1.007276+2\times 1.008665-x){c}^{2}``
`` \Rightarrow x=4.0016\,\mathrm{\,u\,}``
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