NEET-XII-Physics

46: The Nucleus

with Solutions - page 2
Qstn# ii-5 Prvs-QstnNext-Qstn
  • #5
    The graph of ln(R/R0) versus ln A(R = radius of a nucleus and A = its mass number) is
    (a) a straight line
    (b) a parabola
    (c) an ellipse
    (d) none of them.
    digAnsr:   a
    Ans : (a) a straight line
    The average nuclear radius (R) and the mass number of the element (A) has the following relation:
    `` R={R}_{o}{A}^{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$3$}\right.}``
    `` \raisebox{1ex}{$R$}\!\left/ \!\raisebox{-1ex}{${R}_{o}$}\right.={A}^{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$3$}\right.}``
    `` \,\mathrm{\,ln\,}\left(\raisebox{1ex}{$R$}\!\left/ \!\raisebox{-1ex}{${R}_{o}$}\right.\right)=\frac{1}{3}\,\mathrm{\,ln\,}A``
    `` ``
    Therefore, the graph of ln(R/R0) versus ln A is a straight line passing through the origin with slope 1/3.
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