NEET-XII-Physics
43: Bohr's Model and Physics of the Atom
- #5Find the binding energy of a hydrogen atom in the state n = 2.Ans : The binding energy (E) of hydrogen atom is given by
`` E=\frac{-13.6}{{n}^{2}}\,\mathrm{\,eV\,}``
For state n = 2,
`` E=-\frac{13.6}{{\left(2\right)}^{2}}``
`` \Rightarrow E=-3.4\,\mathrm{\,eV\,}``
Thus, binding energy of hydrogen at n = 2 is `` -3.4\,\mathrm{\,eV\,}``.
Page No 384: